SSC CHSL Simplification Questions Solved Problems with Detailed Solutions [Free PDF]

The value of \(441\div\left[270\div\frac\ of\ 35+\left(17\div\frac\right)-\left(8\frac-\frac\right)\right]\) is:

Answer (Detailed Solution Below)

Option 1 : 7 India's Super Teachers for all govt. exams Under One Roof Demo Classes Available* Enroll For Free Now

SSC CHSL Simplification Questions Question 1 Detailed Solution

Concept

Reported 29.7.21 Sunny D4


Calculation

⇒ 441 ÷ [ 270 ÷ 15 + 51 - 6]

⇒ 441 ÷ [ 18 + 51 - 6]

∴ The value of \(441\div\left[270\div\frac\ of\ 35+\left(17\div\frac\right)-\left(8\frac-\frac\right)\right]\) is 7

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SSC CHSL Simplification Questions Question 2:

Simplify the following expression. \(\frac-5\frac\div\frac\times1\frac><\frac\ of\ 1\frac\div\frac>\)Answer (Detailed Solution Below) Option 1 : \(-6\frac<1>\)

SSC CHSL Simplification Questions Question 2 Detailed Solution

Concept

BODMAS rule applies here.

First solve bracket values, after it solves the values related with 'Of', Then Divided value, afterward Multiply values, Then addition and subtractions values.

Calculation

⇒ \(11 - 60\over \) × \(3\over 8\)

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SSC CHSL Simplification Questions Question 3:

The value of \(42 \div 10 - \left(\frac<7>\times \frac\right)\:of\:\frac+\frac\times \frac-\left(\frac \div \frac\right)\) is:

Answer (Detailed Solution Below)

Option 1 : 2.3

SSC CHSL Simplification Questions Question 3 Detailed Solution

Follow the BODMAS rule according to the table given below:

Reported 29.7.21 Sunny D4

⇒ 42 ÷ 10 – 7/12 of 6/5 + 16/3 × 9/10 – (1/6 ÷ 1/36)

⇒ 42 ÷ 10 – 7/12 of 6/5 + 16/3 × 9/10 – (1/6 × 36/1)

⇒ 42 ÷ 10 – 7/12 of 6/5 + 16/3 × 9/10 – 6

⇒ 42 ÷ 10 – 7/10 + 16/3 × 9/10 – 6

⇒ 42/10 – 7/10 + 24/5 – 6

∴ The required value is 2.3

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SSC CHSL Simplification Questions Question 4:

Answer (Detailed Solution Below)

Option 1 : 4

SSC CHSL Simplification Questions Question 4 Detailed Solution

Given:

Concept used:

Bodmas dtp

Calculation:

⇒ 200/11 ÷ [7/33 + 13/3]

Required answer is 4

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SSC CHSL Simplification Questions Question 5:

What is the value of x, if 25% of 480 + 30% of 500 + x% of 90 = 35% of 900?

Answer (Detailed Solution Below)

Option 2 : 50

SSC CHSL Simplification Questions Question 5 Detailed Solution

Calculations :

25% of 480 + 30% of 500 + x% of 90 = 35% of 900

⇒ (25/100) of 480 + (30/100) of 500 + (x/100) of 90 = (35/100) of 900

⇒ 120 + 150 + (9x/10) = 315

The correct choice will be option 2.

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SSC CHSL Simplification Questions Question 6:

The value of \(\left(1\frac<1>\div\frac\right)\div\left[\left(\frac<1>\:of1\frac<1>\right)\div\left(3\frac<1>\:-1\frac<1>\right)\:of\frac-\frac\div2\frac<1>\right]\:of\frac\) is:

Answer (Detailed Solution Below)

Option 3 : 18

SSC CHSL Simplification Questions Question 6 Detailed Solution

Follow the BODMAS rule according to the table given below:

Bodmas

⇒ (9/8 ÷ 3/4) ÷ [(1/2 of 3/2) ÷ (7/2 – 5/4) of 3/4 – 3/4 ÷ 9/4] of 3/4

⇒ (9/8 × 4/3) ÷ [(3/4) ÷ (9/4) of 3/4 – 1/3] of 3/4

⇒ (3/2) ÷ [(3/4) ÷ 27/16 – 1/3] of 3/4

⇒ (3/2) ÷ [3/4 × 16/27 – 1/3] of 3/4

⇒ (3/2) ÷ [4/9 – 1/3] of 3/4

∴ The required value is 18

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SSC CHSL Simplification Questions Question 7:

Evaluate: [7 + 7 × ( 7 + 7 ÷ 7)] + 7 ÷ 7.

Answer (Detailed Solution Below)

Option 2 : 64

SSC CHSL Simplification Questions Question 7 Detailed Solution

Given:

[7 + 7 × ( 7 + 7 ÷ 7)] + 7 ÷ 7.

Concept used:

BODMAS

Calculation:

⇒ [7 + 7 × ( 7 + 7 ÷ 7)] + 7 ÷ 7.

∴ The value is 64.

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SSC CHSL Simplification Questions Question 8:

The value of \(8 - [8 - (5 + 8) - \ < 8 - (8 - 5 + 8)\>+ 10]\) is:

Answer (Detailed Solution Below)

Option 3 : 0

SSC CHSL Simplification Questions Question 8 Detailed Solution

Given :

\(8 - [8 - (5 + 8) - \ < 8 - (8 - 5 + 8)\>+ 10]\)

Concept used :

quesImage4840

Calculation :

∴ This value is 0

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SSC CHSL Simplification Questions Question 9:

The value of ? in 10 – [121 ÷ (11 × 11) – (- 4) – <3 – (8 – 1)>] = ? is:

Answer (Detailed Solution Below)

Option 3 : 1

SSC CHSL Simplification Questions Question 9 Detailed Solution

Concept Used:

quesImage3967

Calculations:

Considering the given equation,

⇒ 10 – [121 ÷ (121) + 4 + 4] = ?

⇒ 10 – [121/121 + 4 + 4] = ?

∴ The value of ? is 1.

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SSC CHSL Simplification Questions Question 10:

The value of \(\left[ 5 \frac 4 9 ÷ \left( \frac <11>4 - \frac 6 \right)^2 \right]\) ÷ [ \(7\frac 3 <11>\) of \(8 \frac 4 5 \div 1 \frac 5 7 - \frac 4 3\) ] 2 is:

  1. \(\frac 1 \)
  2. \(\frac 1 \)
  3. \(\frac 1 \)
  4. \(\frac 1 \)

Answer (Detailed Solution Below)

Option 3 : \(\frac 1 <81>\)

SSC CHSL Simplification Questions Question 10 Detailed Solution

Concept used:

Follow BODMAS rule to solve this question, as per the order given below,

quesImage508

Calculation:

\(\left[ 5 \frac 4 9 ÷ \left( \frac 4 - \frac 6 \right)^2 \right] ÷ [7\frac 3 \: of\: 8 \frac 4 5 \div 1 \frac 5 7 - \frac 4 3]^2\)

∴ 1/81

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SSC CHSL Simplification Questions Question 11:

The simplified value of 3 × 6 ÷ 4 of 6 – 6 ÷ 2 × (4 - 6) + 4 – 2 × 3 ÷ 6 of 1/3 is:

Answer (Detailed Solution Below)

Option 3 : \(7\frac<3>\)

SSC CHSL Simplification Questions Question 11 Detailed Solution

Concept used:

qImage32105

Calculation:

3 × 6 ÷ 4 of 6 – 6 ÷ 2 × (4 - 6) + 4 – 2 × 3 ÷ 6 of 1/3

⇒ 3 × 6 ÷ 4 of 6 – 6 ÷ 2 × -2 + 4 – 2 × 3 ÷ 6 of 1/3

⇒ 3 × 6 ÷ 24 – 6 ÷ 2 × -2 + 4 – 2 × 3 ÷ 2

⇒ 3 × 1/4 – 3 × -2 + 4 – 2 × 3/2

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SSC CHSL Simplification Questions Question 12:

The simplified value of \(\frac^< - 6>>>>>\) is:
  • 1.0005
  • 1.0525
  • 1.0505
  • 1.0025
  • Answer (Detailed Solution Below)

    Option 2 : 1.0525

    SSC CHSL Simplification Questions Question 12 Detailed Solution

    Calculation:

    ∴ The correct answer is 1.0525 .

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    SSC CHSL Simplification Questions Question 13:

    The simplified value of \(\Rightarrow \frac<1> \ of \ \frac\div \left\lbrace 2\frac<1>-\left(\frac+ \frac\times 1 \frac\div \frac\right)\right\rbrace\) is:

    Answer (Detailed Solution Below)

    Option 2 : 4

    SSC CHSL Simplification Questions Question 13 Detailed Solution

    Follow BODMAS rule to solve this question, as per the order given below,

    Step - 1 - Parts of an equation enclosed in 'Brackets' must be solved first,

    Step - 2 - Any mathematical 'Of' or 'Exponent' must be solved next,

    Step - 3 - Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

    Step - 4 - Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

    Now, given expression:

    \(\Rightarrow \frac \ of \ \frac\div \left\lbrace 2\frac-\left(\frac+ \frac\times 1 \frac\div \frac\right)\right\rbrace\)

    \(\Rightarrow \frac\times \frac\div \left\lbrace \frac-\left( \frac + \frac\times \frac \div \frac\right)\right\rbrace\)

    \(\Rightarrow \ \frac\div \left\lbrace \frac-\left(\frac+ \frac \times \frac\times \frac\right)\right\rbrace\)

    \(\Rightarrow \frac\div \left\lbrace \frac-\left(\frac+\frac\right)\right\rbrace\)

    \(\Rightarrow \ \frac\div \left\lbrace \frac-\frac\right\rbrace\)

    \(\Rightarrow \frac\times \frac=4\)